Environment - simulationEnvironment: startTime=0 stopTime=2500 tolerance=0.001 numberOfIntervals=2500 stepSize=1 Regular simulation: ./ThermoSysPro_ThermoSysPro.Fluid.Examples.CombinedCyclePowerPlant.CombinedCycle_Load_100_50 -abortSlowSimulation -alarm=480 -lv LOG_STATS LOG_STDOUT | info | Using sparse solver kinsol for nonlinear system 7 (6422), | | | | because density of 0.06 remains under threshold of 0.10. LOG_STDOUT | info | The maximum density for using sparse solvers can be specified | | | | using the runtime flag '<-nlssMaxDensity=value>'. LOG_STDOUT | warning | While solving non-linear system an assertion failed during initialization. | | | | | The non-linear solver tries to solve the problem that could take some time. | | | | | It could help to provide better start-values for the iteration variables. | | | | | For more information simulate with -lv LOG_NLS_V LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21535e+10 | | | | fb = f(u_max) = 2.21619e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.86268e+10 | | | | fb = f(u_max) = 2.86352e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -5.94439e+10 | | | | fb = f(u_max) = -5.94359e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1.17346e+10 | | | | fb = f(u_max) = 1.17429e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.15752e+10 | | | | fb = f(u_max) = 2.15835e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21871e+10 | | | | fb = f(u_max) = 2.21955e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -3.68538e+08 | | | | fb = f(u_max) = -3.60298e+08 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 7.00987e+10 | | | | fb = f(u_max) = 7.01072e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1.44211e+11 | | | | fb = f(u_max) = 1.4422e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21874e+10 | | | | fb = f(u_max) = 2.21957e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 3.52105e+10 | | | | fb = f(u_max) = 3.52189e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21535e+10 | | | | fb = f(u_max) = 2.21619e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21535e+10 | | | | fb = f(u_max) = 2.21619e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.86268e+10 | | | | fb = f(u_max) = 2.86352e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -5.94439e+10 | | | | fb = f(u_max) = -5.94359e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1.17346e+10 | | | | fb = f(u_max) = 1.17429e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.15752e+10 | | | | fb = f(u_max) = 2.15835e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21871e+10 | | | | fb = f(u_max) = 2.21955e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -3.68538e+08 | | | | fb = f(u_max) = -3.60298e+08 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 7.00987e+10 | | | | fb = f(u_max) = 7.01072e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1.44211e+11 | | | | fb = f(u_max) = 1.4422e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21874e+10 | | | | fb = f(u_max) = 2.21957e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 3.52105e+10 | | | | fb = f(u_max) = 3.52189e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_STDOUT | warning | While solving non-linear system an assertion failed during initialization. | | | | | The non-linear solver tries to solve the problem that could take some time. | | | | | It could help to provide better start-values for the iteration variables. | | | | | For more information simulate with -lv LOG_NLS_V LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.69004e+11 | | | | fb = f(u_max) = 2.69012e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -1.60365e+11 | | | | fb = f(u_max) = -1.60357e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1.57014e+11 | | | | fb = f(u_max) = 1.57023e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.30199e+11 | | | | fb = f(u_max) = 2.30208e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34924e+11 | | | | fb = f(u_max) = 2.34933e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1.39347e+11 | | | | fb = f(u_max) = 1.39356e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 4.81447e+11 | | | | fb = f(u_max) = 4.81455e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 8.73203e+11 | | | | fb = f(u_max) = 8.73212e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.88187e+11 | | | | fb = f(u_max) = 2.88196e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21535e+10 | | | | fb = f(u_max) = 2.21619e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -1.54678e+07 | | | | fb = f(u_max) = -7.53684e+06 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -4.97877e+10 | | | | fb = f(u_max) = -4.97796e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21535e+10 | | | | fb = f(u_max) = 2.21619e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -1.54678e+07 | | | | fb = f(u_max) = -7.53684e+06 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -4.97877e+10 | | | | fb = f(u_max) = -4.97796e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.21535e+10 | | | | fb = f(u_max) = 2.21619e+10 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -1.69618e+08 | | | | fb = f(u_max) = -1.61601e+08 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -1.69618e+08 | | | | fb = f(u_max) = -1.61601e+08 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -1.69618e+08 | | | | fb = f(u_max) = -1.61601e+08 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -2.15213e+07 | | | | fb = f(u_max) = -1.35766e+07 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.34926e+11 | | | | fb = f(u_max) = 2.34934e+11 | | | | fa and fb must have opposite sign which is not the case LOG_ASSERT | debug | Solving non-linear system 1254 failed at time=0. | | | | For more information please use -lv LOG_NLS. LOG_ASSERT | info | simulation terminated by an assertion at initialization