Environment - simulationEnvironment: startTime=0 stopTime=1000 tolerance=1e-06 numberOfIntervals=2500 stepSize=0.4 Regular simulation: ./ThermoSysPro_ThermoSysPro.Fluid.Examples.SimpleExamples.TestAirHumidity -abortSlowSimulation -alarm=480 -lv LOG_STATS assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 8953.66 | | | | fb = f(u_max) = 7.93737e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 4004.78 | | | | fb = f(u_max) = 7.91252e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 763.27 | | | | fb = f(u_max) = 7.89624e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 6676.83 | | | | fb = f(u_max) = 7.92593e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 3904.15 | | | | fb = f(u_max) = 7.91201e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2088.05 | | | | fb = f(u_max) = 7.90289e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 898.498 | | | | fb = f(u_max) = 7.89692e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 119.344 | | | | fb = f(u_max) = 7.89301e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 7358.41 | | | | fb = f(u_max) = 7.92936e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 4684.87 | | | | fb = f(u_max) = 7.91593e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2933.69 | | | | fb = f(u_max) = 7.90714e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1786.67 | | | | fb = f(u_max) = 7.90138e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1035.37 | | | | fb = f(u_max) = 7.89761e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 543.274 | | | | fb = f(u_max) = 7.89514e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 220.949 | | | | fb = f(u_max) = 7.89352e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 9.82554 | | | | fb = f(u_max) = 7.89246e+06 | | | | fa and fb must have opposite sign which is not the case stdout | warning | While solving non-linear system an assertion failed during initialization. | | | | | The non-linear solver tries to solve the problem that could take some time. | | | | | It could help to provide better start-values for the iteration variables. | | | | | For more information simulate with -lv LOG_NLS_V assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 19028.3 | | | | fb = f(u_max) = 7.98796e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 12790.5 | | | | fb = f(u_max) = 7.95663e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 12790.5 | | | | fb = f(u_max) = 7.95663e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 822797 | | | | fb = f(u_max) = 1.20239e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 822797 | | | | fb = f(u_max) = 1.20239e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 822797 | | | | fb = f(u_max) = 1.20239e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2292.88 | | | | fb = f(u_max) = 7.90392e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2284.16 | | | | fb = f(u_max) = 7.90388e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 366.156 | | | | fb = f(u_max) = 7.89425e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 1324.1 | | | | fb = f(u_max) = 7.89906e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 365.521 | | | | fb = f(u_max) = 7.89424e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 844.531 | | | | fb = f(u_max) = 7.89665e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 365.355 | | | | fb = f(u_max) = 7.89424e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 125.766 | | | | fb = f(u_max) = 7.89304e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 5.97187 | | | | fb = f(u_max) = 7.89244e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 65.8646 | | | | fb = f(u_max) = 7.89274e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 5.96923 | | | | fb = f(u_max) = 7.89244e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -3.45948e+06 | | | | fb = f(u_max) = -9.47872e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = -1.38103e+10 | | | | fb = f(u_max) = -6.93378e+10 | | | | fa and fb must have opposite sign which is not the case stdout | warning | While solving non-linear system an assertion failed during initialization. | | | | | The non-linear solver tries to solve the problem that could take some time. | | | | | It could help to provide better start-values for the iteration variables. | | | | | For more information simulate with -lv LOG_NLS_V assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 19028.3 | | | | fb = f(u_max) = 7.98796e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 12790.5 | | | | fb = f(u_max) = 7.95663e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 12790.5 | | | | fb = f(u_max) = 7.95663e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 822797 | | | | fb = f(u_max) = 1.20239e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 822797 | | | | fb = f(u_max) = 1.20239e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 822797 | | | | fb = f(u_max) = 1.20239e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 2.31443e+06 | | | | fb = f(u_max) = 1.95139e+07 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 52725 | | | | fb = f(u_max) = 8.15716e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | The arguments u_min and u_max provided in the function call | | | | solveOneNonlinearEquation(f,u_min,u_max) | | | | do not bracket the root of the single non-linear equation 0=f(u): | | | | u_min = 200 | | | | u_max = 6000 | | | | fa = f(u_min) = 238801 | | | | fb = f(u_max) = 9.0915e+06 | | | | fa and fb must have opposite sign which is not the case assert | debug | Solving non-linear system 33 failed at time=0. | | | | For more information please use -lv LOG_NLS. assert | info | simulation terminated by an assertion at initialization