startTime=0
stopTime=1200
tolerance=1e-06
numberOfIntervals=2500
stepSize=0.48
Regular simulation: ./ThermoSysPro_ThermoSysPro.Fluid.Examples.SimpleExamples.TestGasTurbine  -abortSlowSimulation -alarm=480 -lv LOG_STATS
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.201e+10
|                 | |       |   fb = f(u_max) = 1.2019e+10
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 4.45931e+08
|                 | |       |   fb = f(u_max) = 4.5456e+08
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -4.61188e+07
|                 | |       |   fb = f(u_max) = -3.77395e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -3.03516e+07
|                 | |       |   fb = f(u_max) = -2.21359e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.73667e+07
|                 | |       |   fb = f(u_max) = -9.25823e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.12224e+07
|                 | |       |   fb = f(u_max) = -3.18421e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.34402e+07
|                 | |       |   fb = f(u_max) = -4.49488e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -8.79067e+06
|                 | |       |   fb = f(u_max) = -201454
|                 | |       | fa and fb must have opposite sign which is not the case
stdout            | warning | While solving non-linear system an assertion failed during initialization.
|                 | |       | | The non-linear solver tries to solve the problem that could take some time.
|                 | |       | | It could help to provide better start-values for the iteration variables.
|                 | |       | | For more information simulate with -lv LOG_NLS_V
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.68137e+07
|                 | |       |   fb = f(u_max) = -8.56778e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.55246e+09
|                 | |       |   fb = f(u_max) = 2.5607e+09
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.68137e+07
|                 | |       |   fb = f(u_max) = -8.56778e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.55246e+09
|                 | |       |   fb = f(u_max) = 2.5607e+09
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.87094e+08
|                 | |       |   fb = f(u_max) = 1.96031e+08
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.87094e+08
|                 | |       |   fb = f(u_max) = 1.96031e+08
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.87094e+08
|                 | |       |   fb = f(u_max) = 1.96031e+08
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.20992e+07
|                 | |       |   fb = f(u_max) = -1.38033e+07
|                 | |       | fa and fb must have opposite sign which is not the case
stdout            | warning | While solving non-linear system an assertion failed during initialization.
|                 | |       | | The non-linear solver tries to solve the problem that could take some time.
|                 | |       | | It could help to provide better start-values for the iteration variables.
|                 | |       | | For more information simulate with -lv LOG_NLS_V
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 6.4999e+10
|                 | |       |   fb = f(u_max) = 6.50073e+10
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 4.90368e+10
|                 | |       |   fb = f(u_max) = 4.90451e+10
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 3.75351e+13
|                 | |       |   fb = f(u_max) = 3.75351e+13
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_SUCCESS       | info    | The initialization finished successfully without homotopy method.
LOG_STATS         | info    | ### STATISTICS ###
|                 | |       | | timer
|                 | |       | | |   0.00615907s          reading init.xml
|                 | |       | | |  0.000528752s          reading info.xml
|                 | |       | | |   6.7848e-05s [  0.0%] pre-initialization
|                 | |       | | |     0.209047s [  8.8%] initialization
|                 | |       | | |  0.000240191s [  0.0%] steps
|                 | |       | | |   3.2413e-05s [  0.0%] solver (excl. callbacks)
|                 | |       | | |            0s [  0.0%] creating output-file
|                 | |       | | |    0.0231226s [  1.0%] event-handling
|                 | |       | | |    0.0193557s [  0.8%] overhead
|                 | |       | | |       2.1182s [ 89.4%] simulation
|                 | |       | | |      2.37007s [100.0%] total
|                 | |       | | events
|                 | |       | | |     2 state events
|                 | |       | | |     0 time events
|                 | |       | | solver: euler
|                 | |       | | | 10004 steps taken
|                 | |       | | | 10004 calls of functionODE
|                 | |       | | |     0 evaluations of jacobian
|                 | |       | | |     0 error test failures
|                 | |       | | |     0 convergence test failures
|                 | |       | | | 0s time of jacobian evaluation
LOG_SUCCESS       | info    | The simulation finished successfully.