Environment - simulationEnvironment:
startTime=0
stopTime=2500
tolerance=0.001
numberOfIntervals=2500
stepSize=1
Regular simulation: ./ThermoSysPro_ThermoSysPro.Fluid.Examples.CombinedCyclePowerPlant.CombinedCycle_Load_100_50  -abortSlowSimulation -alarm=480 -s gbode -lv LOG_STATS
LOG_STDOUT        | info    | Using sparse solver kinsol for nonlinear system 7 (6422),
|                 | |       | because density of 0.06 remains under threshold of 0.10.
LOG_STDOUT        | info    | The maximum density for using sparse solvers can be specified
|                 | |       | using the runtime flag '<-nlssMaxDensity=value>'.
LOG_STDOUT        | warning | Numerical Jacobians without coloring are currently not supported by GBODE. Colored numerical Jacobian will be used.
LOG_STDOUT        | warning | While solving non-linear system an assertion failed during initialization.
|                 | |       | | The non-linear solver tries to solve the problem that could take some time.
|                 | |       | | It could help to provide better start-values for the iteration variables.
|                 | |       | | For more information simulate with -lv LOG_NLS_V
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21536e+10
|                 | |       |   fb = f(u_max) = 2.2162e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.86269e+10
|                 | |       |   fb = f(u_max) = 2.86353e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -5.94438e+10
|                 | |       |   fb = f(u_max) = -5.94358e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.17347e+10
|                 | |       |   fb = f(u_max) = 1.1743e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.15753e+10
|                 | |       |   fb = f(u_max) = 2.15836e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21873e+10
|                 | |       |   fb = f(u_max) = 2.21956e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -3.6843e+08
|                 | |       |   fb = f(u_max) = -3.6019e+08
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 7.00988e+10
|                 | |       |   fb = f(u_max) = 7.01073e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.44211e+11
|                 | |       |   fb = f(u_max) = 1.4422e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21875e+10
|                 | |       |   fb = f(u_max) = 2.21959e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 3.52106e+10
|                 | |       |   fb = f(u_max) = 3.5219e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21536e+10
|                 | |       |   fb = f(u_max) = 2.2162e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21536e+10
|                 | |       |   fb = f(u_max) = 2.2162e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.86269e+10
|                 | |       |   fb = f(u_max) = 2.86353e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -5.94438e+10
|                 | |       |   fb = f(u_max) = -5.94358e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.17347e+10
|                 | |       |   fb = f(u_max) = 1.1743e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.15753e+10
|                 | |       |   fb = f(u_max) = 2.15836e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21873e+10
|                 | |       |   fb = f(u_max) = 2.21956e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -3.6843e+08
|                 | |       |   fb = f(u_max) = -3.6019e+08
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 7.00988e+10
|                 | |       |   fb = f(u_max) = 7.01073e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.44211e+11
|                 | |       |   fb = f(u_max) = 1.4422e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21875e+10
|                 | |       |   fb = f(u_max) = 2.21959e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 3.52106e+10
|                 | |       |   fb = f(u_max) = 3.5219e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_STDOUT        | warning | While solving non-linear system an assertion failed during initialization.
|                 | |       | | The non-linear solver tries to solve the problem that could take some time.
|                 | |       | | It could help to provide better start-values for the iteration variables.
|                 | |       | | For more information simulate with -lv LOG_NLS_V
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.69004e+11
|                 | |       |   fb = f(u_max) = 2.69013e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.60364e+11
|                 | |       |   fb = f(u_max) = -1.60356e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.57015e+11
|                 | |       |   fb = f(u_max) = 1.57023e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.302e+11
|                 | |       |   fb = f(u_max) = 2.30208e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34925e+11
|                 | |       |   fb = f(u_max) = 2.34933e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 1.39348e+11
|                 | |       |   fb = f(u_max) = 1.39356e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 4.81447e+11
|                 | |       |   fb = f(u_max) = 4.81456e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 8.73204e+11
|                 | |       |   fb = f(u_max) = 8.73213e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.88188e+11
|                 | |       |   fb = f(u_max) = 2.88196e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21536e+10
|                 | |       |   fb = f(u_max) = 2.2162e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.54678e+07
|                 | |       |   fb = f(u_max) = -7.53684e+06
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -4.97879e+10
|                 | |       |   fb = f(u_max) = -4.97798e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21536e+10
|                 | |       |   fb = f(u_max) = 2.2162e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.54678e+07
|                 | |       |   fb = f(u_max) = -7.53684e+06
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -4.97879e+10
|                 | |       |   fb = f(u_max) = -4.97798e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.21536e+10
|                 | |       |   fb = f(u_max) = 2.2162e+10
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.69618e+08
|                 | |       |   fb = f(u_max) = -1.61601e+08
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.69618e+08
|                 | |       |   fb = f(u_max) = -1.61601e+08
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -1.69618e+08
|                 | |       |   fb = f(u_max) = -1.61601e+08
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34926e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = -2.15213e+07
|                 | |       |   fb = f(u_max) = -1.35766e+07
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 200
|                 | |       |   u_max  = 6000
|                 | |       |   fa = f(u_min) = 2.34927e+11
|                 | |       |   fb = f(u_max) = 2.34935e+11
|                 | |       | fa and fb must have opposite sign which is not the case
LOG_ASSERT        | debug   | Solving non-linear system 1254 failed at time=0.
|                 | |       | For more information please use -lv LOG_NLS.
LOG_ASSERT        | info    | simulation terminated by an assertion at initialization