startTime=0
stopTime=10
tolerance=1e-05
numberOfIntervals=2500
stepSize=0.004
Regular simulation: ./ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState -abortSlowSimulation -alarm=480   -emit_protected -lv LOG_STATS
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0650209)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-0.401878)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-0.0745232)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
stdout            | warning | While solving non-linear system an assertion failed during initialization.
|                 | |       | | The non-linear solver tries to solve the problem that could take some time.
|                 | |       | | It could help to provide better start-values for the iteration variables.
|                 | |       | | For more information simulate with -lv LOG_NLS_V
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -616646
|                 | |       |   fb = f(u_max) = -116588
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -646923
|                 | |       |   fb = f(u_max) = -147193
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650262
|                 | |       |   fb = f(u_max) = -150810
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649698
|                 | |       |   fb = f(u_max) = -150613
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650052
|                 | |       |   fb = f(u_max) = -150604
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649476
|                 | |       |   fb = f(u_max) = -150613
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649542
|                 | |       |   fb = f(u_max) = -150091
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -652497
|                 | |       |   fb = f(u_max) = -150666
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650299
|                 | |       |   fb = f(u_max) = -150602
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650225
|                 | |       |   fb = f(u_max) = -150605
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.00290288)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650700
|                 | |       |   fb = f(u_max) = -150596
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730481
|                 | |       |   fb = f(u_max) = -146742
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.00440486)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650904
|                 | |       |   fb = f(u_max) = -150596
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650187
|                 | |       |   fb = f(u_max) = -150604
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650783
|                 | |       |   fb = f(u_max) = -150525
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650025
|                 | |       |   fb = f(u_max) = -150572
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651339
|                 | |       |   fb = f(u_max) = -150592
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-0.127524)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650734
|                 | |       |   fb = f(u_max) = -150598
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650009
|                 | |       |   fb = f(u_max) = -150605
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-0.789644)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-1.87968)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650472
|                 | |       |   fb = f(u_max) = -150600
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650497
|                 | |       |   fb = f(u_max) = -150599
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651266
|                 | |       |   fb = f(u_max) = -150593
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649622
|                 | |       |   fb = f(u_max) = -150608
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649864
|                 | |       |   fb = f(u_max) = -150606
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-2.1843)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650651
|                 | |       |   fb = f(u_max) = -150598
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -655718
|                 | |       |   fb = f(u_max) = -150550
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -652773
|                 | |       |   fb = f(u_max) = -150578
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650297
|                 | |       |   fb = f(u_max) = -150602
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0648139)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649699
|                 | |       |   fb = f(u_max) = -150686
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0105243)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0292597)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -652089
|                 | |       |   fb = f(u_max) = -150585
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650844
|                 | |       |   fb = f(u_max) = -150675
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-0.0317776)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -652047
|                 | |       |   fb = f(u_max) = -150585
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650169
|                 | |       |   fb = f(u_max) = -150425
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650604
|                 | |       |   fb = f(u_max) = -150599
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-0.127517)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.000469336)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-0.127523)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650315
|                 | |       |   fb = f(u_max) = -150602
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650255
|                 | |       |   fb = f(u_max) = -150424
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650782
|                 | |       |   fb = f(u_max) = -150592
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0695604)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649550
|                 | |       |   fb = f(u_max) = -150784
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -506808
|                 | |       |   fb = f(u_max) = -118717
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650057
|                 | |       |   fb = f(u_max) = -150604
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649907
|                 | |       |   fb = f(u_max) = -150116
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0035137)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650052
|                 | |       |   fb = f(u_max) = -150599
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650492
|                 | |       |   fb = f(u_max) = -150600
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650267
|                 | |       |   fb = f(u_max) = -150602
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650057
|                 | |       |   fb = f(u_max) = -150604
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650637
|                 | |       |   fb = f(u_max) = -150599
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -647931
|                 | |       |   fb = f(u_max) = -150627
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650054
|                 | |       |   fb = f(u_max) = -150604
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -652028
|                 | |       |   fb = f(u_max) = -150585
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650589
|                 | |       |   fb = f(u_max) = -150599
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649864
|                 | |       |   fb = f(u_max) = -150606
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.00242288)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650178
|                 | |       |   fb = f(u_max) = -150603
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650057
|                 | |       |   fb = f(u_max) = -150604
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650561
|                 | |       |   fb = f(u_max) = -150599
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651991
|                 | |       |   fb = f(u_max) = -150585
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -653056
|                 | |       |   fb = f(u_max) = -150575
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649864
|                 | |       |   fb = f(u_max) = -150606
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -648509
|                 | |       |   fb = f(u_max) = -150619
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -649490
|                 | |       |   fb = f(u_max) = -150610
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650911
|                 | |       |   fb = f(u_max) = -16245.2
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650911
|                 | |       |   fb = f(u_max) = -16245.2
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-53.3865)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730292
|                 | |       |   fb = f(u_max) = -230291
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-0.138246)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-2.94586)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-10.4732)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.69911e+06
|                 | |       |   fb = f(u_max) = -1.20359e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.64464e+06
|                 | |       |   fb = f(u_max) = -1.16263e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -777355
|                 | |       |   fb = f(u_max) = -285000
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.15953e+06
|                 | |       |   fb = f(u_max) = -1.6682e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28131e+06
|                 | |       |   fb = f(u_max) = -1.79034e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.76895e+06
|                 | |       |   fb = f(u_max) = -1.2734e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97698e+06
|                 | |       |   fb = f(u_max) = -1.48532e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28044e+06
|                 | |       |   fb = f(u_max) = -1.78946e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.26407e+06
|                 | |       |   fb = f(u_max) = -1.77313e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27905e+06
|                 | |       |   fb = f(u_max) = -1.78808e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.90128e+06
|                 | |       |   fb = f(u_max) = -1.40514e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -729245
|                 | |       |   fb = f(u_max) = -237260
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.3332e+06
|                 | |       |   fb = f(u_max) = -1.84236e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.94348e+06
|                 | |       |   fb = f(u_max) = 2.44806e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 16859
|                 | |       |   fb = f(u_max) = 518454
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28447e+06
|                 | |       |   fb = f(u_max) = -1.7935e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 161494
|                 | |       |   fb = f(u_max) = 663022
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28137e+06
|                 | |       |   fb = f(u_max) = -1.79041e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-0.0258478)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-1.56715)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27239e+06
|                 | |       |   fb = f(u_max) = -1.78131e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13339)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692923
|                 | |       |   fb = f(u_max) = -191259
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13231)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28122e+06
|                 | |       |   fb = f(u_max) = -1.79026e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28142e+06
|                 | |       |   fb = f(u_max) = -1.79046e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692731
|                 | |       |   fb = f(u_max) = -191068
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28184e+06
|                 | |       |   fb = f(u_max) = -1.79089e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.2806e+06
|                 | |       |   fb = f(u_max) = -1.78963e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-8.08246)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-1.3882)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.975487)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-9.58517)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 848691
|                 | |       |   fb = f(u_max) = 1.33378e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.02978e+06
|                 | |       |   fb = f(u_max) = -1.53407e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.51756e+06
|                 | |       |   fb = f(u_max) = -1.02738e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97376e+06
|                 | |       |   fb = f(u_max) = -1.48578e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28068e+06
|                 | |       |   fb = f(u_max) = -1.78972e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.33311e+06
|                 | |       |   fb = f(u_max) = -1.68668e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.11052e+06
|                 | |       |   fb = f(u_max) = -1.6197e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 917907
|                 | |       |   fb = f(u_max) = 1.4166e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28506e+06
|                 | |       |   fb = f(u_max) = -1.79412e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-0.138246)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-2.94586)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-10.4732)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.69911e+06
|                 | |       |   fb = f(u_max) = -1.20359e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.64464e+06
|                 | |       |   fb = f(u_max) = -1.16263e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -777355
|                 | |       |   fb = f(u_max) = -285000
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.15953e+06
|                 | |       |   fb = f(u_max) = -1.6682e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28131e+06
|                 | |       |   fb = f(u_max) = -1.79034e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.76895e+06
|                 | |       |   fb = f(u_max) = -1.2734e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97698e+06
|                 | |       |   fb = f(u_max) = -1.48532e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28044e+06
|                 | |       |   fb = f(u_max) = -1.78946e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.26407e+06
|                 | |       |   fb = f(u_max) = -1.77313e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27905e+06
|                 | |       |   fb = f(u_max) = -1.78808e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.90128e+06
|                 | |       |   fb = f(u_max) = -1.40514e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -729245
|                 | |       |   fb = f(u_max) = -237260
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.3332e+06
|                 | |       |   fb = f(u_max) = -1.84236e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.94348e+06
|                 | |       |   fb = f(u_max) = 2.44806e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 16859
|                 | |       |   fb = f(u_max) = 518454
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28447e+06
|                 | |       |   fb = f(u_max) = -1.7935e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 161494
|                 | |       |   fb = f(u_max) = 663022
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28137e+06
|                 | |       |   fb = f(u_max) = -1.79041e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-0.0258478)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-1.56715)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27239e+06
|                 | |       |   fb = f(u_max) = -1.78131e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13339)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692923
|                 | |       |   fb = f(u_max) = -191259
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13231)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28122e+06
|                 | |       |   fb = f(u_max) = -1.79026e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28142e+06
|                 | |       |   fb = f(u_max) = -1.79046e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692731
|                 | |       |   fb = f(u_max) = -191068
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28184e+06
|                 | |       |   fb = f(u_max) = -1.79089e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.2806e+06
|                 | |       |   fb = f(u_max) = -1.78963e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-8.08246)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-1.3882)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.975487)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-9.58517)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 848691
|                 | |       |   fb = f(u_max) = 1.33378e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.02978e+06
|                 | |       |   fb = f(u_max) = -1.53407e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.51756e+06
|                 | |       |   fb = f(u_max) = -1.02738e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97376e+06
|                 | |       |   fb = f(u_max) = -1.48578e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28068e+06
|                 | |       |   fb = f(u_max) = -1.78972e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.33311e+06
|                 | |       |   fb = f(u_max) = -1.68668e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.11052e+06
|                 | |       |   fb = f(u_max) = -1.6197e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 917907
|                 | |       |   fb = f(u_max) = 1.4166e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28506e+06
|                 | |       |   fb = f(u_max) = -1.79412e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-3.67989)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-0.148827)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-6.42972)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730292
|                 | |       |   fb = f(u_max) = -230291
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-0.148827)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-6.42972)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-0.148827)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-6.42972)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650911
|                 | |       |   fb = f(u_max) = -16245.2
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-53.3865)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730292
|                 | |       |   fb = f(u_max) = -230291
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650911
|                 | |       |   fb = f(u_max) = -16245.2
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-53.3865)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730292
|                 | |       |   fb = f(u_max) = -230291
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650911
|                 | |       |   fb = f(u_max) = -16245.2
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-53.3865)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730292
|                 | |       |   fb = f(u_max) = -230291
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650911
|                 | |       |   fb = f(u_max) = -16245.2
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-53.3865)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730292
|                 | |       |   fb = f(u_max) = -230291
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -650911
|                 | |       |   fb = f(u_max) = -16245.2
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -651411
|                 | |       |   fb = f(u_max) = -150591
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-53.3865)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -730292
|                 | |       |   fb = f(u_max) = -230291
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-88.1227)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.0919529)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-0.12159)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:13937: Invalid root: (-0.46137)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
stdout            | warning | While solving non-linear system an assertion failed during initialization.
|                 | |       | | The non-linear solver tries to solve the problem that could take some time.
|                 | |       | | It could help to provide better start-values for the iteration variables.
|                 | |       | | For more information simulate with -lv LOG_NLS_V
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -905568
|                 | |       |   fb = f(u_max) = -407886
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.06815e+06
|                 | |       |   fb = f(u_max) = -577699
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-1.64606)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.17215e+06
|                 | |       |   fb = f(u_max) = -675515
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25864e+06
|                 | |       |   fb = f(u_max) = -761284
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761274
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -882122
|                 | |       |   fb = f(u_max) = -384284
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.1527e+06
|                 | |       |   fb = f(u_max) = -655348
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761289
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25903e+06
|                 | |       |   fb = f(u_max) = -761668
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.2556e+06
|                 | |       |   fb = f(u_max) = -758277
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25887e+06
|                 | |       |   fb = f(u_max) = -761508
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -927591
|                 | |       |   fb = f(u_max) = -429444
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:10527: Invalid root: (-1.56673)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.26089e+06
|                 | |       |   fb = f(u_max) = -763492
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.18393e+06
|                 | |       |   fb = f(u_max) = -684862
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 16859
|                 | |       |   fb = f(u_max) = 518454
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25971e+06
|                 | |       |   fb = f(u_max) = -763085
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 161494
|                 | |       |   fb = f(u_max) = 663022
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761272
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25866e+06
|                 | |       |   fb = f(u_max) = -761200
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.62069e+06
|                 | |       |   fb = f(u_max) = -861385
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:3454: Invalid root: (-0.411194)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761289
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761302
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761318
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761271
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25268e+06
|                 | |       |   fb = f(u_max) = -755250
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761294
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761284
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13339)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692923
|                 | |       |   fb = f(u_max) = -191259
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13231)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25867e+06
|                 | |       |   fb = f(u_max) = -761125
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25864e+06
|                 | |       |   fb = f(u_max) = -761375
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692731
|                 | |       |   fb = f(u_max) = -191068
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25909e+06
|                 | |       |   fb = f(u_max) = -761851
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.2581e+06
|                 | |       |   fb = f(u_max) = -760637
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-17.411)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25864e+06
|                 | |       |   fb = f(u_max) = -761280
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-1.3882)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761293
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.975487)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761282
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-21.0289)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 442923
|                 | |       |   fb = f(u_max) = 924137
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.03389e+06
|                 | |       |   fb = f(u_max) = -535945
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -806389
|                 | |       |   fb = f(u_max) = -310631
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.05778e+06
|                 | |       |   fb = f(u_max) = -563795
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25866e+06
|                 | |       |   fb = f(u_max) = -761296
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.27014e+06
|                 | |       |   fb = f(u_max) = -691622
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.16817e+06
|                 | |       |   fb = f(u_max) = -670914
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 472919
|                 | |       |   fb = f(u_max) = 971766
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.26111e+06
|                 | |       |   fb = f(u_max) = -763758
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761289
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25866e+06
|                 | |       |   fb = f(u_max) = -761298
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25866e+06
|                 | |       |   fb = f(u_max) = -761303
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25866e+06
|                 | |       |   fb = f(u_max) = -761303
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761287
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761293
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761302
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25864e+06
|                 | |       |   fb = f(u_max) = -761324
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761274
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761268
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761281
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25864e+06
|                 | |       |   fb = f(u_max) = -761280
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761288
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761289
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761295
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761283
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.28687e+06
|                 | |       |   fb = f(u_max) = 1.74866e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.28687e+06
|                 | |       |   fb = f(u_max) = 1.74866e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-490.425)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 6047.34
|                 | |       |   fb = f(u_max) = 505980
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.69911e+06
|                 | |       |   fb = f(u_max) = -1.20359e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.64464e+06
|                 | |       |   fb = f(u_max) = -1.16263e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -777355
|                 | |       |   fb = f(u_max) = -285000
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.15953e+06
|                 | |       |   fb = f(u_max) = -1.6682e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28131e+06
|                 | |       |   fb = f(u_max) = -1.79034e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.76895e+06
|                 | |       |   fb = f(u_max) = -1.2734e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97698e+06
|                 | |       |   fb = f(u_max) = -1.48532e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28044e+06
|                 | |       |   fb = f(u_max) = -1.78946e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.26407e+06
|                 | |       |   fb = f(u_max) = -1.77313e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27905e+06
|                 | |       |   fb = f(u_max) = -1.78808e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.90128e+06
|                 | |       |   fb = f(u_max) = -1.40514e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -729245
|                 | |       |   fb = f(u_max) = -237260
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.3332e+06
|                 | |       |   fb = f(u_max) = -1.84236e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.94348e+06
|                 | |       |   fb = f(u_max) = 2.44806e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 16859
|                 | |       |   fb = f(u_max) = 518454
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28447e+06
|                 | |       |   fb = f(u_max) = -1.7935e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 161494
|                 | |       |   fb = f(u_max) = 663022
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28137e+06
|                 | |       |   fb = f(u_max) = -1.79041e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-0.0258478)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-1.56758)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27239e+06
|                 | |       |   fb = f(u_max) = -1.78131e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13339)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692923
|                 | |       |   fb = f(u_max) = -191259
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13231)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28122e+06
|                 | |       |   fb = f(u_max) = -1.79026e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28142e+06
|                 | |       |   fb = f(u_max) = -1.79046e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692731
|                 | |       |   fb = f(u_max) = -191068
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28184e+06
|                 | |       |   fb = f(u_max) = -1.79089e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.2806e+06
|                 | |       |   fb = f(u_max) = -1.78963e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-8.08306)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-1.3882)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.975487)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-9.89684)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 848691
|                 | |       |   fb = f(u_max) = 1.33378e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.02978e+06
|                 | |       |   fb = f(u_max) = -1.53407e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.51756e+06
|                 | |       |   fb = f(u_max) = -1.02738e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97376e+06
|                 | |       |   fb = f(u_max) = -1.48577e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28068e+06
|                 | |       |   fb = f(u_max) = -1.78972e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.33311e+06
|                 | |       |   fb = f(u_max) = -1.68668e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.11052e+06
|                 | |       |   fb = f(u_max) = -1.6197e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 917907
|                 | |       |   fb = f(u_max) = 1.4166e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28506e+06
|                 | |       |   fb = f(u_max) = -1.79412e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.69911e+06
|                 | |       |   fb = f(u_max) = -1.20359e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.64464e+06
|                 | |       |   fb = f(u_max) = -1.16263e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -777355
|                 | |       |   fb = f(u_max) = -285000
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.15953e+06
|                 | |       |   fb = f(u_max) = -1.6682e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28131e+06
|                 | |       |   fb = f(u_max) = -1.79034e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.76895e+06
|                 | |       |   fb = f(u_max) = -1.2734e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97698e+06
|                 | |       |   fb = f(u_max) = -1.48532e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28044e+06
|                 | |       |   fb = f(u_max) = -1.78946e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.26407e+06
|                 | |       |   fb = f(u_max) = -1.77313e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27905e+06
|                 | |       |   fb = f(u_max) = -1.78808e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.90128e+06
|                 | |       |   fb = f(u_max) = -1.40514e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -729245
|                 | |       |   fb = f(u_max) = -237260
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.3332e+06
|                 | |       |   fb = f(u_max) = -1.84236e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.94348e+06
|                 | |       |   fb = f(u_max) = 2.44806e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 16859
|                 | |       |   fb = f(u_max) = 518454
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28447e+06
|                 | |       |   fb = f(u_max) = -1.7935e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 161494
|                 | |       |   fb = f(u_max) = 663022
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28137e+06
|                 | |       |   fb = f(u_max) = -1.79041e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-0.0258478)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-1.56758)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.27239e+06
|                 | |       |   fb = f(u_max) = -1.78131e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13339)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692923
|                 | |       |   fb = f(u_max) = -191259
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-3.13231)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28122e+06
|                 | |       |   fb = f(u_max) = -1.79026e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28142e+06
|                 | |       |   fb = f(u_max) = -1.79046e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -692731
|                 | |       |   fb = f(u_max) = -191068
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28184e+06
|                 | |       |   fb = f(u_max) = -1.79089e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.2806e+06
|                 | |       |   fb = f(u_max) = -1.78963e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-8.08306)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-1.3882)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:16370: Invalid root: (-0.975487)^(1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:17531: Invalid root: (-9.89684)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 848691
|                 | |       |   fb = f(u_max) = 1.33378e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.02978e+06
|                 | |       |   fb = f(u_max) = -1.53407e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.51756e+06
|                 | |       |   fb = f(u_max) = -1.02738e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.97376e+06
|                 | |       |   fb = f(u_max) = -1.48577e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28068e+06
|                 | |       |   fb = f(u_max) = -1.78972e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.33311e+06
|                 | |       |   fb = f(u_max) = -1.68668e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.11052e+06
|                 | |       |   fb = f(u_max) = -1.6197e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 917907
|                 | |       |   fb = f(u_max) = 1.4166e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28506e+06
|                 | |       |   fb = f(u_max) = -1.79412e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79036e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28134e+06
|                 | |       |   fb = f(u_max) = -1.79038e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28132e+06
|                 | |       |   fb = f(u_max) = -1.79035e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -2.28133e+06
|                 | |       |   fb = f(u_max) = -1.79037e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-10.1614)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 6047.34
|                 | |       |   fb = f(u_max) = 505980
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:11611: Invalid root: (-0.145619)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.28687e+06
|                 | |       |   fb = f(u_max) = 1.74866e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-490.425)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 6047.34
|                 | |       |   fb = f(u_max) = 505980
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.28687e+06
|                 | |       |   fb = f(u_max) = 1.74866e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-490.425)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 6047.34
|                 | |       |   fb = f(u_max) = 505980
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.28687e+06
|                 | |       |   fb = f(u_max) = 1.74866e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-490.425)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 6047.34
|                 | |       |   fb = f(u_max) = 505980
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.28687e+06
|                 | |       |   fb = f(u_max) = 1.74866e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-490.425)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 6047.34
|                 | |       |   fb = f(u_max) = 505980
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.28687e+06
|                 | |       |   fb = f(u_max) = 1.74866e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25865e+06
|                 | |       |   fb = f(u_max) = -761290
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | ModelicaTest_4.0.0_ModelicaTest.Fluid.TestExamplesVariants.BranchingDynamicPipes_MomentumSteadyState_functions.c:4615: Invalid root: (-490.425)^(-1.5)
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 6047.34
|                 | |       |   fb = f(u_max) = 505980
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.12539e+06
|                 | |       |   fb = f(u_max) = -332205
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = 1.08184e+06
|                 | |       |   fb = f(u_max) = 1.79339e+06
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | The arguments u_min and u_max provided in the function call
|                 | |       |     solveOneNonlinearEquation(f,u_min,u_max)
|                 | |       | do not bracket the root of the single non-linear equation 0=f(u):
|                 | |       |   u_min  = 190
|                 | |       |   u_max  = 647
|                 | |       |   fa = f(u_min) = -1.25863e+06
|                 | |       |   fb = f(u_max) = -761269
|                 | |       | fa and fb must have opposite sign which is not the case
assert            | debug   | Solving non-linear system 2329 failed at time=0.
|                 | |       | For more information please use -lv LOG_NLS.
assert            | error   | Failed to solve the initialization problem with global homotopy with equidistant step size.
assert            | debug   | Unable to solve initialization problem.
assert            | info    | simulation terminated by an assertion at initialization